When a capillary tube is dipped into a tub co | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For a liquid that does not wet the surface (like mercury), the meniscus is convex upwards.According to the Young-Laplace equation, the pressure di

Vedclass · Accepted Answer

more than the atmospheric pressure

Vedclass · Answer

(D) For a liquid that does not wet the surface (like mercury), the meniscus is convex upwards.According to the Young-Laplace equation, the pressure difference across a curved surface is given by $\Delta P = P_{out} - P_{in} = \frac{2T}{R}$.For a convex meniscus, the pressure just below the meniscus $(P_{in})$ is greater than the pressure just above it $(P_{out})$.Since the pressure just above the meniscus is the atmospheric pressure $(P_0)$, the pressure just below the meniscus is $P_{in} = P_0 + \frac{2T}{R}$.Therefore, the pressure just below the meniscus is more than the atmospheric pressure, which causes the mercury level to be depressed in the capillary tube.

When a capillary tube is dipped into a tub containing mercury, the mercury level in the capillary goes down because the pressure just below the meniscus is

Similar Questions

When a mercury drop of radius $R$ breaks into $n$ droplets of equal size,the radius $r$ of each droplet is

Due to surface tension, the excess pressure inside a smaller drop is $9$ units. If $27$ smaller drops combine, then the excess pressure inside the bigger drop is:

Two droplets merge with each other and form a large droplet. In this process,

$A$ soap bubble in vacuum has a radius of $3 \, cm$ and another soap bubble in vacuum has a radius of $4 \, cm$. If the two bubbles coalesce under isothermal condition,then the radius of the new bubble is ....... $cm$.

The work done to break a spherical drop of radius $R$ into $n$ drops of equal size is proportional to .............

Vedclass Test Series

Exam Paper Generator

Online Exam Module