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(B) According to Faraday's law of induction, the induced electromotive force $(EMF)$ is given by $\varepsilon = -L \frac{di}{dt}$.Since the current $i

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Constant and it will be in a direction opposite to $i$

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(B) According to Faraday's law of induction, the induced electromotive force $(EMF)$ is given by $\varepsilon = -L \frac{di}{dt}$.Since the current $i$ is increasing at a constant rate, $\frac{di}{dt} = 	ext{constant}$.Therefore, the induced $EMF$ $\varepsilon$ is constant, which implies that the induced current $I_{	ext{ind}} = \frac{\varepsilon}{R}$ is also constant.According to Lenz's law, the induced current always opposes the change in magnetic flux that produced it.Since the original current $i$ is increasing, the induced current will flow in a direction opposite to the original current $i$ to oppose this increase.

When a current $i$ through a solenoid is increasing at a constant rate, then the induced current is

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