When a current of $10 \ A$ is passed through molten $AlCl_{3}$ for $1.608 \ minutes$,the mass of $Al$ deposited will be [Atomic mass of $Al = 27 \ g/mol$]:- (in $g$)

  • A
    $0.09$
  • B
    $0.81$
  • C
    $1.35$
  • D
    $0.27$

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