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(A) Given:Current $I = 4 \ mA = 4 	imes 10^{-3} \ A$Magnetic flux $\phi = 32 	imes 10^{-6} \ Wb$ (or $T \ m^2$)First,calculate the self-inductance $

Vedclass · Accepted Answer

$64 	imes 10^{-9} \ J$

Vedclass · Answer

(A) Given:Current $I = 4 \ mA = 4 	imes 10^{-3} \ A$Magnetic flux $\phi = 32 	imes 10^{-6} \ Wb$ (or $T \ m^2$)First,calculate the self-inductance $L$ using the formula $\phi = L \cdot I$:$L = \frac{\phi}{I} = \frac{32 	imes 10^{-6}}{4 	imes 10^{-3}} = 8 	imes 10^{-3} \ H$The energy stored in an inductor is given by $U = \frac{1}{2} L I^2$:$U = \frac{1}{2} 	imes (8 	imes 10^{-3}) 	imes (4 	imes 10^{-3})^2$$U = 4 	imes 10^{-3} 	imes 16 	imes 10^{-6}$$U = 64 	imes 10^{-9} \ J$Therefore,the correct option is $A$.

When a current of $4 \ mA$ passes through an inductor,if the flux linked with it is $32 \times 10^{-6} \ T \ m^2$,then the energy stored in the inductor is

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