When a moving coil galvanometer (MCG) is conv | vedclass

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(C) Let $R_{G}$ be the resistance of the galvanometer and $I_{g}$ be the full-scale deflection current.The original voltage range of the galvanometer

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$n+1$

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(C) Let $R_{G}$ be the resistance of the galvanometer and $I_{g}$ be the full-scale deflection current.The original voltage range of the galvanometer is $V_{g} = I_{g}R_{G}$.When a series resistance $R_{s} = nR_{G}$ is added to convert it into a voltmeter,the new voltage range $V$ is given by:$V = I_{g}(R_{s} + R_{G})$Substitute $R_{s} = nR_{G}$ into the equation:$V = I_{g}(nR_{G} + R_{G})$$V = I_{g}R_{G}(n + 1)$Since $V_{g} = I_{g}R_{G}$,we have:$V = V_{g}(n + 1)$Therefore,the voltmeter is now capable of measuring $(n + 1)$ times the original voltage range of the $MCG$.

When a moving coil galvanometer $(MCG)$ is converted into a voltmeter,the series resistance is '$n$' times the resistance of the galvanometer. How many times the original voltage range of the $MCG$ is the voltmeter now capable of measuring?

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