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(C) The kinetic energy $(KE)$ gained by a charged particle when accelerated through a potential difference $(V)$ is given by the formula: $\Delta KE =

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$1$

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(C) The kinetic energy $(KE)$ gained by a charged particle when accelerated through a potential difference $(V)$ is given by the formula: $\Delta KE = qV$.For a proton,the charge is $q = e$.Given the potential difference $V = 1\,V$.Substituting these values,we get: $\Delta KE = e 	imes 1\,V = 1\,eV$.Therefore,the kinetic energy of the proton is $1\,eV$.

When a proton is accelerated through $1\,V,$ then its kinetic energy will be........$eV$.

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