When a solution of a mixture having two inorg | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. The formation of a dark brown ring with freshly prepared ferrous sulphate in an acidic medium is the characteristic test for the nitrate ion

Vedclass · Accepted Answer

$CH_3COO^{-}$ and $NO_3^{-}$

Vedclass · Answer

(A) $1$. The formation of a dark brown ring with freshly prepared ferrous sulphate in an acidic medium is the characteristic test for the nitrate ion $(NO_3^{-})$,known as the Brown Ring Test: $2NO_3^{-} + 4H_2SO_4 + 6Fe^{2+} \rightarrow 6Fe^{3+} + 2NO + 4SO_4^{2-} + 4H_2O$ followed by $[Fe(H_2O)_6]^{2+} + NO \rightarrow [Fe(H_2O)_5(NO)]^{2+} + H_2O$ (brown ring).$2$. The formation of a deep red colour with neutral $FeCl_3$ is the characteristic test for the acetate ion $(CH_3COO^{-})$,which forms ferric acetate: $CH_3COO^{-} + FeCl_3 \rightarrow [Fe_3(OH)_2(CH_3COO)_6]^+$. This red colour disappears on boiling,resulting in a brown-red precipitate of basic ferric acetate: $[Fe_3(OH)_2(CH_3COO)_6]^+ + 4H_2O \rightarrow 3Fe(OH)_2(CH_3COO) \downarrow + 3CH_3COOH + H^+$.$3$. Therefore,the mixture contains $CH_3COO^{-}$ and $NO_3^{-}$.

Similar Questions

When $BaCl_2$ is added to a clear solution of compound $(X)$,a heavy white precipitate is formed,which is insoluble in dilute $HCl$. What is compound $(X)$?

$A$ salt solution is treated with chloroform drops. Then it is shaken with chlorine water. The chloroform layer becomes violet. The solution contains:

$Na_2CO_3$ cannot be used to identify which of the following ions?

Chromyl chloride vapours are dissolved in $NaOH$ and acetic acid and lead acetate solution is added,then

Vedclass Test Series

Exam Paper Generator

Online Exam Module