(A) The maximum velocity $(v_{\max})$ of a particle in simple harmonic motion is given by the formula $v_{\max} = a\omega$,where $a$ is the amplitude

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(A) The maximum velocity $(v_{\max})$ of a particle in simple harmonic motion is given by the formula $v_{\max} = a\omega$,where $a$ is the amplitude and $\omega$ is the angular frequency.Given:Amplitude $a = 0.1 \text{ cm}$Frequency $n = 300 \text{ Hz}$Angular frequency $\omega = 2\pi n = 2 \times \pi \times 300 = 600\pi \text{ rad/s}$.Substituting these values into the formula:$v_{\max} = 0.1 \times 600\pi = 60\pi \text{ cm/s}$.Therefore,the maximum velocity of the particle is $60\pi \text{ cm/s}$.

Class 11 Physics Waves and Sound Sound Waves (Longitudinal wave) and it’s Characteristics (Speed etc.)

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When a sound wave of frequency $300 Hz$ passes through a medium,the maximum displacement of a particle of the medium is $0.1 cm$. The maximum velocity of the particle is equal to:

A
$60\pi \text{ cm/s}$
B
$30\pi \text{ cm/s}$
C
$30 \text{ cm/s}$
D
$60 \text{ cm/s}$

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Sound Waves (Longitudinal wave) and it’s Characteristics (Speed etc.)

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When a sound wave of frequency $300 Hz$ passes through a medium,the maximum displacement of a particle of the medium is $0.1 cm$. The maximum velocity of the particle is equal to:

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Two monoatomic ideal gases '$1$' and '$2$' of molecular masses $m_1$ and $m_2$ respectively are enclosed in separate containers kept at the same temperature. The ratio of the speed of sound in gas '$1$' to that in gas '$2$' is

If $v_m$ is the velocity of sound in moist air and $v_d$ is the velocity of sound in dry air,under identical conditions of pressure and temperature,then:

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