When a spaceship is two earth radii distant f | vedclass

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(C) The gravitational acceleration $g$ at a distance $r$ from the centre of the Earth is given by the formula $g' = \frac{GM}{r^2}$.At the surface of

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$2.45$

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(C) The gravitational acceleration $g$ at a distance $r$ from the centre of the Earth is given by the formula $g' = \frac{GM}{r^2}$.At the surface of the Earth,the distance $r = R$ (where $R$ is the radius of the Earth),so $g = \frac{GM}{R^2} = 9.8\, m s^{-2}$.Given that the spaceship is at a distance $r = 2R$ from the centre of the Earth.Substituting this into the formula: $g' = \frac{GM}{(2R)^2} = \frac{GM}{4R^2}$.Since $g = \frac{GM}{R^2}$,we can write $g' = \frac{g}{4}$.Substituting the value of $g = 9.8\, m s^{-2}$,we get $g' = \frac{9.8}{4} = 2.45\, m s^{-2}$.

When a spaceship is two earth radii distant from the centre of the earth,its gravitational acceleration is: (in $, m s^{-2}$)

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