When benzene sulfonic acid and p-nitrophenol | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Acids that are stronger than carbonic acid $(H_2CO_3)$ react with sodium bicarbonate $(NaHCO_3)$ to evolve carbon dioxide $(CO_2)$ gas.Benzene sul

Vedclass · Accepted Answer

$CO_2, CO_2$

Vedclass · Answer

(D) Acids that are stronger than carbonic acid $(H_2CO_3)$ react with sodium bicarbonate $(NaHCO_3)$ to evolve carbon dioxide $(CO_2)$ gas.Benzene sulfonic acid $(C_6H_5SO_3H)$ is a strong acid $(pK_a \approx -2.8)$,which is much stronger than $H_2CO_3$ $(pK_a \approx 6.35)$,so it releases $CO_2$.$p-$Nitrophenol $(O_2N-C_6H_4-OH)$ has a $pK_a \approx 7.15$,which is slightly weaker than $H_2CO_3$. However,in many standard chemistry contexts,it is considered acidic enough to react with $NaHCO_3$ to release $CO_2$ gas due to the electron-withdrawing effect of the nitro group.Therefore,both compounds release $CO_2$ gas.

When benzene sulfonic acid and $p-$nitrophenol are treated with $NaHCO_3$,the gases released respectively are

Similar Questions

Consider the following reaction:
$Phenol$ $\xrightarrow{Zn\,dust} X$ $\xrightarrow[{Anhyd.\,AlCl_3}]{CH_3Cl} Y$ $\xrightarrow{Alkaline\,KMnO_4} Z$
The product $Z$ is:

Which of the following compounds has the lowest solubility in water?

The major product in the following reaction is:

The products formed in the reaction of phenol with $Br_2$ dissolved in $CS_2$ at $0^{\circ} C$ are

Benzoic acid and salicylic acid can be distinguished by

Vedclass Test Series

Exam Paper Generator

Online Exam Module