When calomel reacts with NH_4OH solution,the | vedclass

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Question

(C) Calomel is $Hg_2Cl_2$. When it reacts with $NH_4OH$,it undergoes a disproportionation reaction to form a black mixture of metallic mercury $(Hg)$

Vedclass · Accepted Answer

$Hg(NH_2)Cl$

Vedclass · Answer

(C) Calomel is $Hg_2Cl_2$. When it reacts with $NH_4OH$,it undergoes a disproportionation reaction to form a black mixture of metallic mercury $(Hg)$ and amino mercuric chloride $(Hg(NH_2)Cl)$.The balanced chemical equation is:$Hg_2Cl_2 + 2NH_4OH \rightarrow Hg + Hg(NH_2)Cl + NH_4Cl + 2H_2O$Thus,the compound formed is $Hg(NH_2)Cl$.

When calomel reacts with $NH_4OH$ solution,the compound formed is

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