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Question

(A) The brown ring test is used to detect the presence of nitrate ions $(NO_3^-)$ in a solution.$1$. The nitrate ion reacts with concentrated sulphuri

Vedclass · Accepted Answer

$[Fe(H_2O)_5NO]SO_4$

Vedclass · Answer

(A) The brown ring test is used to detect the presence of nitrate ions $(NO_3^-)$ in a solution.$1$. The nitrate ion reacts with concentrated sulphuric acid $(H_2SO_4)$ to produce nitric acid $(HNO_3)$:$NO_3^- + H_2SO_4 	o HNO_3 + HSO_4^-$$2$. The nitric acid is then reduced by ferrous sulphate $(FeSO_4)$ to form nitric oxide $(NO)$:$2HNO_3 + 6FeSO_4 + 3H_2SO_4 	o 3Fe_2(SO_4)_3 + 2NO + 4H_2O$$3$. The nitric oxide $(NO)$ reacts with the remaining ferrous sulphate to form the brown complex:$[Fe(H_2O)_6]^{2+} + NO 	o [Fe(H_2O)_5NO]^{2+} + H_2O$The composition of the brown ring is $[Fe(H_2O)_5NO]SO_4$.

When concentrated sulphuric acid is added slowly to a solution of ferrous sulphate containing nitrate ion,a brown coloured ring is formed. The composition of the ring is

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