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(C) The magnifying power $(M)$ of an astronomical telescope is given by the ratio of the focal length of the objective $(f_o)$ to the focal length of

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Magnifying power remains the same but resolving power is increased

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(C) The magnifying power $(M)$ of an astronomical telescope is given by the ratio of the focal length of the objective $(f_o)$ to the focal length of the eyepiece $(f_e)$,i.e.,$M = f_o / f_e$. Since the focal lengths of the lenses do not change when the diameter of the aperture is increased,the magnifying power remains the same. The resolving power of a telescope is defined as $1 / \Delta	heta = D / 1.22\lambda$,where $D$ is the diameter of the objective aperture and $\lambda$ is the wavelength of light. As the diameter $D$ increases,the resolving power increases. Additionally,the light-gathering capacity (intensity of the image) increases as it is proportional to the square of the diameter $(I \propto D^2)$.

When the diameter of the aperture of the objective of an astronomical telescope is increased,its

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