When iodine reacts with NaF, NaBr and NaCl, w | vedclass

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(D) Iodine $(I_2)$ is the least electronegative and the weakest oxidizing agent among the halogens $(F_2, Cl_2, Br_2, I_2)$.Therefore,it cannot displa

Vedclass · Accepted Answer

None of these.

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(D) Iodine $(I_2)$ is the least electronegative and the weakest oxidizing agent among the halogens $(F_2, Cl_2, Br_2, I_2)$.Therefore,it cannot displace other halogens from their respective salt solutions $(NaF, NaBr, NaCl)$.Thus,the reactions $I_2 + NaF \xrightarrow{} 	ext{No reaction}$,$I_2 + NaBr \xrightarrow{} 	ext{No reaction}$,and $I_2 + NaCl \xrightarrow{} 	ext{No reaction}$ do not occur.The correct option is $D$.

When iodine reacts with $NaF,$ $NaBr$ and $NaCl,$ what happens?

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