When mercury $(II)$ chloride is treated with excess of $SnCl_2$,the products obtained are

  • A
    Liquid $Hg, SnCl_4$
  • B
    $Hg_2Cl_2, SnCl_4$
  • C
    $Hg_2Cl_2, [SnCl_4]^{2-}$
  • D
    Liquid $Hg, SnCl_4$

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