When one CO_2 molecule is fixed as one molecu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In the Calvin cycle,the reduction phase involves the conversion of $3$-phosphoglycerate ($3$-$PGA$) to glyceraldehyde $3$-phosphate (triose phosph

Vedclass · Accepted Answer

$1\,ATP + 1\,NADPH$

Vedclass · Answer

(A) In the Calvin cycle,the reduction phase involves the conversion of $3$-phosphoglycerate ($3$-$PGA$) to glyceraldehyde $3$-phosphate (triose phosphate).For the fixation of one molecule of $CO_2$,the reduction phase requires $1$ molecule of $ATP$ (for phosphorylation) and $1$ molecule of $NADPH$ (for reduction).However,the overall stoichiometry for the production of one molecule of triose phosphate from $3$ molecules of $CO_2$ requires $6$ $ATP$ and $6$ $NADPH$ in the reduction phase.Therefore,for the fixation of a single $CO_2$ molecule,the requirement is $1$ $ATP$ and $1$ $NADPH$ specifically for the reduction step.

When one $CO_2$ molecule is fixed as one molecule of triose phosphate,which of the following photochemically made,high energy chemical intermediates are used in the reduction phase?

Similar Questions

During the dark reaction,the acceptor of $CO_{2}$ is

State the location of the light reaction and the Calvin cycle in $C_3$ plants.

The carbon dioxide acceptor in Calvin cycle ($C_3$ plants) is:

The first stable product of photosynthesis in $C_3$ plants is ...... .

During photosynthesis,when $PGA$ is converted into phosphoglyceraldehyde,which of the following reactions occurs?

Vedclass Test Series

Exam Paper Generator

Online Exam Module