When potassium iodide solution is added to a solution of lead $(II)$ nitrate in a test tube,a precipitate is formed.
$(i)$ Write a balanced chemical equation for this reaction.
$(ii)$ What type of reaction is this?

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(N/A) $(i)$ The balanced chemical equation is:
$2KI(aq) + Pb(NO_3)_2(aq) \to PbI_2(s) \downarrow + 2KNO_3(aq)$
$(ii)$ This is a double displacement reaction. Since an insoluble solid (precipitate) is formed,it is also classified as a precipitation reaction.

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