When the speed of a moving object is doubled, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The kinetic energy $(K.E.)$ of an object of mass $m$ moving with velocity $v$ is given by the formula: $K.E. = \frac{1}{2}mv^2$.If the speed is do

Vedclass · Accepted Answer

kinetic energy increases $4$ times

Vedclass · Answer

(D) The kinetic energy $(K.E.)$ of an object of mass $m$ moving with velocity $v$ is given by the formula: $K.E. = \frac{1}{2}mv^2$.If the speed is doubled,the new velocity becomes $v' = 2v$.The new kinetic energy $(K.E.')$ will be: $K.E.' = \frac{1}{2}m(2v)^2 = \frac{1}{2}m(4v^2) = 4 	imes (\frac{1}{2}mv^2)$.Therefore,$K.E.' = 4 	imes K.E.$This shows that the kinetic energy increases $4$ times when the speed is doubled.

When the speed of a moving object is doubled,its:

Similar Questions

Justify,giving proper reasoning,whether the work done in the following case is positive or negative: Work done by an applied force on a body moving on a rough horizontal plane with uniform velocity.

When is the work done by a force said to be negative? Give one situation in which one of the forces acting on the object is doing positive work and the other is doing negative work.

The potential energy of a person is minimum when:

What is a watt?

$A$ man drops a $10\, kg$ rock from the top of a $5\, m$ ladder. What is its kinetic energy when it reaches the ground? What is its speed just before it hits the ground?

Vedclass Test Series

Exam Paper Generator

Online Exam Module