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(A) The formula for the temperature coefficient of resistance $\alpha$ is given by $\alpha = \frac{R_2 - R_1}{R_1(T_2 - T_1)}$.Given that the resistan

Vedclass · Accepted Answer

$2 	imes 10^{-3} \ K^{-1}$

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(A) The formula for the temperature coefficient of resistance $\alpha$ is given by $\alpha = \frac{R_2 - R_1}{R_1(T_2 - T_1)}$.Given that the resistance increases by $10 \%$,we have $R_2 = R_1 + 0.10 R_1 = 1.1 R_1$.The change in temperature is $\Delta T = T_2 - T_1 = 356 \ K - 303 \ K = 53 \ K$.Substituting these values into the formula:$\alpha = \frac{1.1 R_1 - R_1}{R_1(53)} = \frac{0.1 R_1}{53 R_1} = \frac{0.1}{53}$.$\alpha \approx 0.001886 \ K^{-1} \approx 1.886 	imes 10^{-3} \ K^{-1}$.Rounding to the nearest significant option,we get $\alpha \approx 2 	imes 10^{-3} \ K^{-1}$.

When the temperature of a wire is increased from $303 \ K$ to $356 \ K$,the resistance of the wire increases by $10 \%$. The temperature coefficient of resistance of the material of the wire is:

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