When the value of R in the balanced Wheatston | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to the balanced condition of a Wheatstone bridge, the ratio of resistances in opposite arms is equal: $\frac{P}{Q} = \frac{R}{S}$.In the

Vedclass · Accepted Answer

$7.5$

Vedclass · Answer

(D) According to the balanced condition of a Wheatstone bridge, the ratio of resistances in opposite arms is equal: $\frac{P}{Q} = \frac{R}{S}$.In the first case:$\frac{P}{Q} = \frac{5}{S} \quad \dots(i)$In the second case, $R$ is increased to $7 \Omega$ and $S$ is increased by $3 \Omega$ (i.e.,$S + 3 \Omega$):$\frac{P}{Q} = \frac{7}{S + 3} \quad \dots(ii)$Equating $(i)$ and $(ii)$:$\frac{5}{S} = \frac{7}{S + 3}$$5(S + 3) = 7S$$5S + 15 = 7S$$2S = 15$$S = 7.5 \Omega$Thus, the initial value of $S$ is $7.5 \Omega$.

When the value of $R$ in the balanced Wheatstone bridge, shown in the figure, is increased from $5 \Omega$ to $7 \Omega$, the value of $S$ has to be increased by $3 \Omega$ in order to maintain the balance. What is the initial value of $S$ (in $\Omega$)?

Similar Questions

What is a Wheatstone bridge? Explain its principle.

The given figure shows a network of resistances and a battery. Choose the correct statement$(s)$.

The equivalent resistance between the points $A$ and $B$ in the following circuit is $\frac{x}{5} \Omega$. The value of $x$ is . . . . . . .

In the given figure,all the batteries are ideal. Find the value of $i$ (in amperes).

The value of current $I$ in the given current distribution is: (in $A$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module