When there is no external force,the shape of a liquid drop is determined by

$A$ wooden stick of length $2 \ m$ floats on water. The surface tension of water is $0.07 \ N/m$. If a soap solution with a surface tension of $0.06 \ N/m$ is applied to one side of the stick,what will be the net force acting on it in $N$?

The shape of a liquid drop becomes spherical due to

$A$ square wire frame of each side $L$ is dipped in soap solution. On taking out, a membrane is formed. If the surface tension of the solution is $T$, the force acting on the frame will be (in $T L$)

If a section of a soap bubble (of radius $R$) through its center is considered, then the force on one half due to surface tension is

$A$ wire of length $20 \ cm$ is placed horizontally on the surface of water and is gently pulled up with a force of $1.456 \times 10^{-2} \ N$ to keep the wire in equilibrium. The surface tension of water is (in $N \ m^{-1}$)