When three forces of 50 , N,30 , N,and 15 , N | vedclass

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(D) For a body to be in equilibrium under the action of three forces,the vector sum of the forces must be zero. This is possible if the magnitude of a

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Moving with an acceleration

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(D) For a body to be in equilibrium under the action of three forces,the vector sum of the forces must be zero. This is possible if the magnitude of any one force is less than or equal to the sum of the other two forces and greater than or equal to the difference of the other two forces. Here,the forces are $F_1 = 50 \, N$,$F_2 = 30 \, N$,and $F_3 = 15 \, N$. The sum of the two smaller forces is $30 \, N + 15 \, N = 45 \, N$. Since $50 \, N > 45 \, N$,the three forces cannot form a closed triangle,meaning their vector sum cannot be zero. Because the net force is non-zero,the body will experience a net force and will move with an acceleration according to Newton's Second Law of Motion.

When three forces of $50 \, N$,$30 \, N$,and $15 \, N$ act on a body,then the body is

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