When two coaxial coils having the same current in the same direction are brought closer to each other,what happens to the value of the current in both coils?

$A$ magnetic field $4 \times 10^{-2} \, T$ acts at right angles to a coil of area $100 \, cm^2$ with $50$ turns. The average e.m.f. induced in the coil is $0.1 \, V$, when it is removed from the field in time '$t$'. The value of '$t$' is

$A$ current-carrying solenoid is approaching a conducting loop as shown in the figure. The direction of the induced current as observed by an observer on the other side of the loop will be

$A$ long solenoid of diameter $0.1\, m$ has $2 \times 10^4$ turns per meter. At the centre of the solenoid,a coil of $100$ turns and radius $0.01\, m$ is placed with its axis coinciding with the solenoid axis. The current in the solenoid reduces at a constant rate to $0\, A$ from $4\, A$ in $0.05\, s$. If the resistance of the coil is $10\pi^2\, \Omega$,the total charge flowing through the coil during this time is:

$A$ magnet is moved in the direction indicated by an arrow between two coils $AB$ and $CD$ as shown in the figure. The direction of the induced current in the coils is

The magnetic flux through a loop of resistance $10 \Omega$ is given by $\phi = 5t^2 - 4t + 1 \text{ Wb}$. How much current is induced in the loop after $0.2 \text{ s}$ (in $\text{ A}$)?