Which among the following cations will form t | vedclass

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(C) The stability of a metal complex is inversely proportional to the size of the metal cation. As the size of the cation increases,the electrostatic

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$Cd^{2+}$

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(C) The stability of a metal complex is inversely proportional to the size of the metal cation. As the size of the cation increases,the electrostatic attraction between the metal ion and the ligand decreases,leading to lower stability. Among the given cations ($Cu^{2+}$,$Fe^{2+}$,$Cd^{2+}$,$Ni^{2+}$),$Cd^{2+}$ has the largest ionic radius. Therefore,$Cd^{2+}$ forms the complex with the lowest stability.

Which among the following cations will form the lowest stability complex if the ligand remains the same?

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The correct order of molar conductivity of the following complex compounds in aqueous solution is:
$(I) K[Co(NH_3)_2(NO_2)_4]$
$(II) [Cr(NH_3)_3(NO_2)_3]$
$(III) [Cr(NH_3)_5NO_2]_3[Co(NO_2)_6]_2$
$(IV) Mg[Cr(NH_3)(NO_2)_5]$

In $[Fe(CO)_5]$,the $Fe-C$ bond has

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