Which among the following compounds will unde | vedclass

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(C) The rate of $S_{N}2$ reaction depends on the steric hindrance around the electrophilic carbon atom. The order of reactivity is: $Methyl \ halide >

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(C) The rate of $S_{N}2$ reaction depends on the steric hindrance around the electrophilic carbon atom. The order of reactivity is: $Methyl \ halide > 1^{\circ} \ halide > 2^{\circ} \ halide > 3^{\circ} \ halide$.In the given options:$(A)$ is a $3^{\circ}$ alkyl halide.$(B)$ is a $3^{\circ}$ alkyl halide.$(C)$ is a $1^{\circ}$ alkyl halide (cyclobutyl-methyl bromide).$(D)$ is a $2^{\circ}$ alkyl halide.Since $1^{\circ}$ alkyl halides have the least steric hindrance,they undergo $S_{N}2$ reactions the fastest. Therefore,cyclobutyl-methyl bromide will undergo the fastest $S_{N}2$ reaction.

List-$I$ (Reaction)	List-$II$ (Mechanism)
$A$. Williamson Synthesis	$I$. Electrophilic addition
$B$. Friedel-Crafts Reaction	$II$. Free radical substitution
$C$. Bromination of vinyl benzene	$III$. Nucleophilic substitution
$D$. Chlorination of toluene in light	$IV$. Electrophilic substitution

Which among the following compounds will undergo the fastest $S_{N}2$ reaction?

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