Which among the following is most paramagneti | vedclass

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(B) Paramagnetic character depends on the number of unpaired electrons in the $d$-subshell.In these complex ions,$H_2O$ is a weak field ligand,so the

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$[Fe(H_2O)_6]^{2+}$

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(B) Paramagnetic character depends on the number of unpaired electrons in the $d$-subshell.In these complex ions,$H_2O$ is a weak field ligand,so the electrons remain unpaired according to Hund's rule:$(a)$ In $[Cr(H_2O)_6]^{3+}$,$Cr^{3+}$ has a $3d^3$ configuration. Number of unpaired electrons $= 3$.$(b)$ In $[Fe(H_2O)_6]^{2+}$,$Fe^{2+}$ has a $3d^6$ configuration. In an octahedral field,this corresponds to $t_{2g}^4 e_g^2$,resulting in $4$ unpaired electrons.$(c)$ In $[Cu(H_2O)_6]^{2+}$,$Cu^{2+}$ has a $3d^9$ configuration. Number of unpaired electrons $= 1$.$(d)$ In $[Zn(H_2O)_6]^{2+}$,$Zn^{2+}$ has a $3d^{10}$ configuration. Number of unpaired electrons $= 0$.Since paramagnetic character is directly proportional to the number of unpaired electrons,$[Fe(H_2O)_6]^{2+}$ is the most paramagnetic.

Which among the following is most paramagnetic?

Similar Questions

Identify the number of complexes that are optically active:
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The coordination compound with the molecular formula $[CO(NO_2)(SCN)(en)_2]Br$ exhibits which of the following types of isomerism?

How many geometrical isomers and stereoisomers are possible for $[Pt(NO_2)(NH_3)(NH_2OH)(Py)]^+$ and $[Pt(Br)(Cl)(I)(NO_2)(NH_3)(Py)]$ respectively?

Draw all the isomers (geometrical and optical) of:
$(i)$ $[CoCl_2(en)_2]^+$
$(ii)$ $[Co(NH_3)Cl(en)_2]^{2+}$
$(iii)$ $[Co(NH_3)_2Cl_2(en)]^+$

Which of the following compounds cannot show coordination isomerism?

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