Which among the following is true?

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(B) $1$. Option $A$ is incorrect because alloys with low temperature coefficients of resistance (like Manganin or Constantan) are used,not necessarily

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$\vec{E} = \rho \vec{J}$ is the statement of Ohm's law (where $\vec{E}$ is the electric field and $\vec{J}$ is the current density).

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(B) $1$. Option $A$ is incorrect because alloys with low temperature coefficients of resistance (like Manganin or Constantan) are used,not necessarily those with very low resistivity.$2$. Option $B$ is correct. The microscopic form of Ohm's law is given by $\vec{J} = \sigma \vec{E}$,which can be written as $\vec{E} = \rho \vec{J}$,where $\rho$ is resistivity.$3$. Option $C$ is incorrect because $V = IR$ is only valid for Ohmic conductors,not for non-Ohmic materials like semiconductors or diodes.$4$. Therefore,only statement $B$ is true.

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