Which of the following can show geometrical i | vedclass

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(C) For a molecule to show geometrical isomerism,each carbon atom of the double bond must be attached to two different groups. $(A)$ $Ph_2C=CHCl$: The

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But$-2-$ene

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(C) For a molecule to show geometrical isomerism,each carbon atom of the double bond must be attached to two different groups. $(A)$ $Ph_2C=CHCl$: The left carbon is attached to two identical phenyl $(Ph)$ groups. It does not show geometrical isomerism. $(B)$ $(CH_3)_2C=CHBr$: The left carbon is attached to two identical methyl $(CH_3)$ groups. It does not show geometrical isomerism. $(C)$ $CH_3-CH=CH-CH_3$: Each carbon of the double bond is attached to a hydrogen atom and a methyl group. Since the groups on each carbon are different,it can exist as cis and trans isomers. $(D)$ $H_3C-C \equiv C-CH_3$: This is an alkyne,which has a linear geometry and cannot show geometrical isomerism. Therefore,option $(C)$ is correct.

Which of the following can show geometrical isomerism?

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