Which cannot be used to generate H_{2}? | vedclass

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Question

(C) $Mg + NaOH$ cannot be used to generate hydrogen gas.The reactions leading to the generation of hydrogen gas are as follows:$(A)$ $2Al + 2NaOH + 2H

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$Mg + NaOH$

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(C) $Mg + NaOH$ cannot be used to generate hydrogen gas.The reactions leading to the generation of hydrogen gas are as follows:$(A)$ $2Al + 2NaOH + 2H_{2}O \rightarrow 2NaAlO_{2} + 3H_{2}\uparrow$ (sodium meta aluminate)$(B)$ $Zn + 2NaOH \rightarrow Na_{2}ZnO_{2} + H_{2}$$(C)$ $Mg$ is not affected by alkalies. Hence,it does not react with $NaOH$.$(D)$ $LiH + H_{2}O \rightarrow H_{2}\uparrow + LiOH$Therefore,option $C$ is correct.

Which cannot be used to generate $H_{2}$?

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