(C) The stability of a complex is inversely proportional to its dissociation constant $(k_d)$.Lower the value of $k_d$,higher is the stability of the

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$[Fe(CN)_6]^{3-} ; k_d = 1 \times 10^{-44}$

(C) The stability of a complex is inversely proportional to its dissociation constant $(k_d)$.Lower the value of $k_d$,higher is the stability of the complex.Comparing the given values:$1 \times 10^{-16} > 1 \times 10^{-20} > 1 \times 10^{-37} > 1 \times 10^{-44}$.The complex $[Fe(CN)_6]^{3-}$ has the minimum dissociation constant $(k_d = 1 \times 10^{-44})$,therefore it is the most stable complex.

Class 12 Chemistry Coordination Compounds Complexes and complex stability

Medium

Which complex is most stable? Where $k_d =$ Dissociation constant.

A
$[Cu(CN)_2]^-; k_d = 1 \times 10^{-16}$
B
$[Fe(CN)_6]^{4-} ; k_d = 1 \times 10^{-37}$
C
$[Fe(CN)_6]^{3-} ; k_d = 1 \times 10^{-44}$
D
$[Ag(CN)_2]^-; k_d = 1 \times 10^{-20}$

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Complexes and complex stability

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MediumJEE MAIN 2023

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MediumAIIMS 2013

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Which of the following complexes is the most stable: $[Fe(H_2O)_6]^{3+}$,$[Fe(CN)_6]^{3-}$,$[Fe(C_2O_4)_3]^{3-}$,or $[FeCl_6]^{3-}$?

Medium

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Assign $A, B, C, D$ for the type of observation in the following reaction:
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Which complex is most stable? Where $k_d =$ Dissociation constant.

Similar Questions

Transition elements in lower oxidation states act as Lewis acid because

Which of the following complexes is octahedral,diamagnetic,and the most stable?

Assertion : $Cu^{2+}$ and $Cd^{2+}$ are separated from each other by first adding $KCN$ solution and then passing $H_2S$ gas.Reason : $KCN$ reduces $Cu^{2+}$ to $Cu^{+}$ and forms a complex with it.

Which of the following complexes is the most stable: $[Fe(H_2O)_6]^{3+}$,$[Fe(CN)_6]^{3-}$,$[Fe(C_2O_4)_3]^{3-}$,or $[FeCl_6]^{3-}$?

Assign $A, B, C, D$ for the type of observation in the following reaction:$CuSO_4 + KCN \text{ (excess)} \longrightarrow K_3[Cu(CN)_4] + \frac{1}{2}(CN)_2$

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Assertion : $Cu^{2+}$ and $Cd^{2+}$ are separated from each other by first adding $KCN$ solution and then passing $H_2S$ gas.
Reason : $KCN$ reduces $Cu^{2+}$ to $Cu^{+}$ and forms a complex with it.

Assign $A, B, C, D$ for the type of observation in the following reaction:
$CuSO_4 + KCN \text{ (excess)} \longrightarrow K_3[Cu(CN)_4] + \frac{1}{2}(CN)_2$