Which compound will give a yellow precipitate | vedclass

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(D) The reaction with sodium hypoiodite $(NaOI)$ is the iodoform test. Compounds containing the $CH_3CH(OH)-$ group or the $CH_3CO-$ group give a posi

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$sec-$butyl alcohol

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(D) The reaction with sodium hypoiodite $(NaOI)$ is the iodoform test. Compounds containing the $CH_3CH(OH)-$ group or the $CH_3CO-$ group give a positive iodoform test,resulting in a yellow precipitate of iodoform $(CHI_3)$. Among the given options,$sec-$butyl alcohol $(CH_3CH(OH)CH_2CH_3)$ contains the $CH_3CH(OH)-$ structural unit. Therefore,$sec-$butyl alcohol reacts with $NaOI$ to form a yellow precipitate.

Which compound will give a yellow precipitate on reaction with sodium hypoiodite?

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