Which graph best shows the velocity-time grap | vedclass

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(B) When an object is launched vertically upward with air resistance $|D| = bv$,the equation of motion is $m(dv/dt) = -mg - bv$. During the upward mot

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(B) When an object is launched vertically upward with air resistance $|D| = bv$,the equation of motion is $m(dv/dt) = -mg - bv$. During the upward motion,both gravity and air resistance act downward,so the net force is $F = -(mg + bv)$. This causes a larger deceleration compared to the case without air resistance,meaning the velocity decreases more rapidly. During the downward motion,gravity acts downward and air resistance acts upward,so the net force is $F = -mg + bv$. As the object falls,its speed increases,and the upward air resistance increases,which reduces the net downward acceleration. Therefore,the velocity-time graph will show a steeper slope during the upward phase and a flattening slope during the downward phase as it approaches terminal velocity. Graph $B$ correctly depicts these characteristics.

Which graph best shows the velocity-time graph for an object launched vertically into the air when air resistance is given by $|D| = bv$? The dashed line shows the velocity graph if there were no air resistance.

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