Which has the maximum number of molecules?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The number of molecules is directly proportional to the number of moles $(n = \frac{	ext{mass}}{	ext{molar mass}})$.$7 \ g$ $N_2 = \frac{7}{28}

Vedclass · Accepted Answer

$2 \ g$ $H_2$

Vedclass · Answer

(B) The number of molecules is directly proportional to the number of moles $(n = \frac{	ext{mass}}{	ext{molar mass}})$.$7 \ g$ $N_2 = \frac{7}{28} = 0.25 \ mol$$2 \ g$ $H_2 = \frac{2}{2} = 1 \ mol$$16 \ g$ $NO_2 = \frac{16}{46} \approx 0.348 \ mol$$16 \ g$ $O_2 = \frac{16}{32} = 0.5 \ mol$Since $2 \ g$ $H_2$ has the highest number of moles $(1 \ mol)$,it contains the maximum number of molecules.

Similar Questions

Choose the correct option for the mole fraction of both components in a gaseous mixture containing $7 \ g$ of nitrogen and $8 \ g$ of oxygen.

At $STP$,$32 \ g$ of $O_2$ contains $6.022 \times 10^{23}$ molecules. How many atoms does $32 \ g$ of sulfur $(S)$ contain under the same conditions?

The number of atoms in $8 \ g$ of sodium is $x \times 10^{23}$. The value of $x$ is ...... (Nearest integer).
$[ \text{Given}: N_{A} = 6.02 \times 10^{23} \ mol^{-1}, \text{Atomic mass of } Na = 23.0 \ u ]$

How many moles of $Mg_{3}(PO_{4})_{2}$ contain $0.25$ moles of $O$ atoms?

The number of moles in $620 \ g$ of sodium oxide is ..... moles.

Vedclass Test Series

Exam Paper Generator

Online Exam Module