Which is the correct configuration of the giv | vedclass

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(A) To determine the $E/Z$ configuration,we use the Cahn-Ingold-Prelog $(CIP)$ priority rules for the groups attached to each carbon of the double bon

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$E$

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(A) To determine the $E/Z$ configuration,we use the Cahn-Ingold-Prelog $(CIP)$ priority rules for the groups attached to each carbon of the double bond.$1$. For the left carbon: $F$ (atomic number $9$) has higher priority than $Cl$ (atomic number $17$ is higher,but $F$ is directly attached to $C$,so we compare $F$ vs $Cl$. $Cl$ has higher atomic number than $F$,so $Cl$ is priority $(1)$ and $F$ is priority $(2)$).Wait,let's re-evaluate: $Cl$ (atomic number $17$) > $F$ (atomic number $9$). So $Cl$ is $(1)$ and $F$ is $(2)$.$2$. For the right carbon: We compare $-COOH$ and $-CHO$. The first atom is $C$ in both. In $-COOH$,the $C$ is bonded to $(O, O, O)$ (considering the double bond to $O$ as two $O$ atoms). In $-CHO$,the $C$ is bonded to $(O, O, H)$. Since $(O, O, O) > (O, O, H)$,$-COOH$ has priority $(1)$ and $-CHO$ has priority $(2)$.$3$. Looking at the structure: The priority $(1)$ groups ($Cl$ and $-COOH$) are on opposite sides of the double bond.$4$. When the high-priority groups are on opposite sides,the configuration is $E$ (from German 'entgegen').

Which is the correct configuration of the given compound?

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