Which statement is correct for the phenomenon | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The magnetic flux linked with a rotating coil is given by $\phi = BA \cos(\omega t)$,where $\omega$ is the angular speed of rotation.According to

Vedclass · Accepted Answer

Phase difference between induced emf and linked flux is $\pi / 2$.

Vedclass · Answer

(C) The magnetic flux linked with a rotating coil is given by $\phi = BA \cos(\omega t)$,where $\omega$ is the angular speed of rotation.According to Faraday's law of induction,the induced emf $E$ is given by $E = -\frac{d\phi}{dt}$.$E = -\frac{d}{dt}(BA \cos(\omega t)) = -BA(-\omega \sin(\omega t)) = BA\omega \sin(\omega t)$.We can rewrite this as $E = BA\omega \cos(\omega t - \pi / 2)$.Comparing the phase of the flux $\phi$ (which is $\omega t$) and the phase of the induced emf $E$ (which is $\omega t - \pi / 2$),the phase difference is $\pi / 2$.Therefore,the induced emf lags behind the magnetic flux by $\pi / 2$.

Which statement is correct for the phenomenon of periodic electromagnetic induction?

Similar Questions

$A$ circular coil of resistance $R$,area $A$,and number of turns $N$ is rotated about its vertical diameter with angular speed $\omega$ in a uniform magnetic field of magnitude $B$. The average power dissipated in a complete cycle is:

Which statement is correct for the phenomenon of periodic electromagnetic induction in a rotating coil?

When a rectangular coil is rotated in a uniform magnetic field about an axis passing through its centre and perpendicular to the field,the emf induced in the coil varies

Write the equation for the maximum $emf$ in an $AC$ generator.

Vedclass Test Series

Exam Paper Generator

Online Exam Module