Which is correct for the above reaction :- | vedclass

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(D) Step $1$: Benzene reacts with $CH_3Cl$ in the presence of anhydrous $AlCl_3$ (Friedel-Crafts alkylation) to form Toluene $(A)$.Step $2$: Toluene $

Vedclass · Accepted Answer

$C = 	ext{Benzyl isocyanide}$

Vedclass · Answer

(D) Step $1$: Benzene reacts with $CH_3Cl$ in the presence of anhydrous $AlCl_3$ (Friedel-Crafts alkylation) to form Toluene $(A)$.Step $2$: Toluene $(A)$ reacts with $Cl_2$ in the presence of $h
u$ (free radical substitution) to form Benzyl chloride $(B = C_6H_5CH_2Cl)$.Step $3$: Benzyl chloride $(B)$ reacts with $AgCN$. Since $AgCN$ is a covalent compound,the nitrogen atom acts as the nucleophile,leading to the formation of Benzyl isocyanide $(C = C_6H_5CH_2NC)$.Therefore,the correct option is $D$.

Which is correct for the above reaction $:-$

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