Which of the following complexes is diamagnet | vedclass

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(B) complex is diamagnetic if all electrons are paired in the $d$-orbitals.$(A)$ $[CoF_6]^{3-}$: $Co^{3+}$ is $3d^6$. $F^-$ is a weak field ligand,so

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$[Ni(CN)_4]^{2-}$

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(B) complex is diamagnetic if all electrons are paired in the $d$-orbitals.$(A)$ $[CoF_6]^{3-}$: $Co^{3+}$ is $3d^6$. $F^-$ is a weak field ligand,so electrons remain unpaired. It has $4$ unpaired electrons and is paramagnetic.$(B)$ $[Ni(CN)_4]^{2-}$: $Ni^{2+}$ is $3d^8$. $CN^-$ is a strong field ligand,causing pairing. The configuration is $d_{sp^2}$ hybridization with all electrons paired. Thus,it is diamagnetic.$(C)$ $[NiCl_4]^{2-}$: $Ni^{2+}$ is $3d^8$. $Cl^-$ is a weak field ligand. It has $2$ unpaired electrons and is paramagnetic.$(D)$ $[Fe(CN)_6]^{3-}$: $Fe^{3+}$ is $3d^5$. $CN^-$ is a strong field ligand,but $d^5$ configuration results in $1$ unpaired electron. Thus,it is paramagnetic.

Which of the following complexes is diamagnetic?

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