Which is the best synthesis of $1-$methoxy$-2,4-$dinitrobenzene?
- ABenzene $\xrightarrow[FeBr_3]{Br_2}$ Bromobenzene $\xrightarrow[H_2SO_4]{HNO_3}$ $1-$bromo$-4-$nitrobenzene $\xrightarrow[H_2SO_4]{HNO_3}$ $1-$bromo$-2,4-$dinitrobenzene $\xrightarrow[CH_3OH]{NaOCH_3}$ $1-$methoxy$-2,4-$dinitrobenzene
- BBenzene $\xrightarrow[H_2SO_4]{HNO_3}$ Nitrobenzene $\xrightarrow[H_2SO_4]{HNO_3}$ $1,3-$dinitrobenzene $\xrightarrow[FeBr_3]{Br_2}$ $1-$bromo$-2,4-$dinitrobenzene $\xrightarrow[CH_3OH]{NaOCH_3}$ $1-$methoxy$-2,4-$dinitrobenzene
- CBenzene $\xrightarrow[H_2SO_4]{HNO_3}$ Nitrobenzene $\xrightarrow[FeBr_3]{Br_2}$ $1-$bromo$-3-$nitrobenzene $\xrightarrow[H_2SO_4]{HNO_3}$ $1-$bromo$-2,4-$dinitrobenzene $\xrightarrow[CH_3OH]{NaOCH_3}$ $1-$methoxy$-2,4-$dinitrobenzene
- DBenzene $\xrightarrow[H_2SO_4]{HNO_3}$ Nitrobenzene $\xrightarrow[FeBr_3]{Br_2}$ $1-$bromo$-3-$nitrobenzene $\xrightarrow[CH_3OH]{NaOCH_3}$ $1-$methoxy$-3-$nitrobenzene $\xrightarrow[H_2SO_4]{HNO_3}$ $1-$methoxy$-2,4-$dinitrobenzene
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Medium
View SolutionIn chlorobenzene,the $-Cl$ group is deactivating; however,it still undergoes electrophilic aromatic substitution reactions. Column-$(I)$ contains the reagents and Column-$(II)$ contains the products. Match Column-$(I)$ with Column-$(II)$.
| Column-$(I)$ (Reagents) | Column-$(II)$ (Products) |
| :--- | :--- |
| $(A)$ $Cl_2$ / anhydrous $AlCl_3$ | $(i)$ $1$-chloro-$2$-methylbenzene + $1$-chloro-$4$-methylbenzene |
| $(B)$ conc. $HNO_3$ + conc. $H_2SO_4$ | $(ii)$ $2$-chlorobenzenesulfonic acid + $4$-chlorobenzenesulfonic acid |
| $(C)$ conc. $H_2SO_4$ and heat | $(iii)$ $1,2$-dichlorobenzene + $1,4$-dichlorobenzene |
| $(D)$ $CH_3COCl$ in presence of anhydrous $AlCl_3$ | $(iv)$ $2$-chloroacetophenone + $4$-chloroacetophenone |
| | $(v)$ $1$-chloro-$2$-nitrobenzene + $1$-chloro-$4$-nitrobenzene |
| Column-$(I)$ (Reagents) | Column-$(II)$ (Products) |
| :--- | :--- |
| $(A)$ $Cl_2$ / anhydrous $AlCl_3$ | $(i)$ $1$-chloro-$2$-methylbenzene + $1$-chloro-$4$-methylbenzene |
| $(B)$ conc. $HNO_3$ + conc. $H_2SO_4$ | $(ii)$ $2$-chlorobenzenesulfonic acid + $4$-chlorobenzenesulfonic acid |
| $(C)$ conc. $H_2SO_4$ and heat | $(iii)$ $1,2$-dichlorobenzene + $1,4$-dichlorobenzene |
| $(D)$ $CH_3COCl$ in presence of anhydrous $AlCl_3$ | $(iv)$ $2$-chloroacetophenone + $4$-chloroacetophenone |
| | $(v)$ $1$-chloro-$2$-nitrobenzene + $1$-chloro-$4$-nitrobenzene |
Medium
View SolutionTwo benzyne intermediates are likely to be formed equally. Reaction with amide ion can occur in two different directions with each benzyne,giving three possible products. They are formed in a $1 : 2 : 1$ ratio. Asterisk $(*)$ refers to $^{14}C$. Product $(A)$ is:
Difficult
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