Which is the correct order of dipole moments | vedclass

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(C) $BF_3$ has a zero dipole moment due to its symmetrical trigonal planar geometry.In $NH_3$,$N$ is more electronegative than $H$. The bond dipoles o

Vedclass · Accepted Answer

$NH_3 > NF_3 > BF_3$

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(C) $BF_3$ has a zero dipole moment due to its symmetrical trigonal planar geometry.In $NH_3$,$N$ is more electronegative than $H$. The bond dipoles of the three $N-H$ bonds and the lone pair on the nitrogen atom are in the same direction,which reinforces each other,resulting in a high net dipole moment.In $NF_3$,$F$ is more electronegative than $N$. The bond dipoles of the three $N-F$ bonds are in the opposite direction to the dipole moment of the lone pair on the nitrogen atom,which partially cancels out the net dipole moment.Therefore,the dipole moment of $NH_3$ is greater than that of $NF_3$,and $BF_3$ has the lowest (zero) dipole moment.The correct order is $NH_3 > NF_3 > BF_3$.

Which is the correct order of dipole moments of $BF_3$,$NF_3$ and $NH_3$?

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