Which is the correct order of the following alkyl halides for an $S_{N}2$ reaction?

  • A
    $ii > i > iii$
  • B
    $iii > i > ii$
  • C
    $iii > ii > i$
  • D
    $ii > iii > i$

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Similar Questions

Consider the following four reactions: $(I) C_6H_5-CHCl-CH_3 \xrightarrow{95\% \text{ acetone}, 5\% \text{ water}} C_6H_5-CH(OH)-CH_3$ $(II) C_6H_5-CHCl-CH_3 \xrightarrow{90\% \text{ acetone}, 10\% \text{ water}} C_6H_5-CH(OH)-CH_3$ $(III) C_6H_5-CHCl-CH_3 \xrightarrow{80\% \text{ acetone}, 20\% \text{ water}} C_6H_5-CH(OH)-CH_3$ $(IV) C_6H_5-CHCl-CH_3 \xrightarrow{100\% \text{ water}} C_6H_5-CH(OH)-CH_3$ Arrange these reactions in decreasing order of the proportion of inverted product and select the correct answer from the codes given below:

Explain elimination reactions of alkyl halides.
or
Explain dehydrohalogenation ($\beta$-elimination) of alkyl halides.

Which reagents shown below would accomplish the following transformation?
$Isopropyl \ bromide \xrightarrow{1. A \ 2. B} Isopropyl \ alcohol$

In the following reaction sequence,the correct structure$(s)$ of $X$ is (are)
$X$ $\xrightarrow[2) NaI, Me_2CO]{1) PBr_3, Et_2O}$ $\xrightarrow{3) NaN_3, HCONMe_2} \text{enantiomerically pure product}$

Under identical conditions, the $S_{N}1$ reaction will occur most efficiently with

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