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(B) The reaction between a Grignard reagent $(CH_3CH_2MgBr)$ and a ketone $(CH_3COCH_3)$ proceeds via nucleophilic addition to the carbonyl group.$1$.

Vedclass · Accepted Answer

$2-$Methylbutan$-2-$ol

Vedclass · Answer

(B) The reaction between a Grignard reagent $(CH_3CH_2MgBr)$ and a ketone $(CH_3COCH_3)$ proceeds via nucleophilic addition to the carbonyl group.$1$. The ethyl group $(CH_3CH_2^-)$ acts as a nucleophile and attacks the electrophilic carbonyl carbon of propanone.$2$. This forms an intermediate magnesium alkoxide: $(CH_3)_2C(OMgBr)(CH_2CH_3)$.$3$. Subsequent acid hydrolysis of this intermediate yields the tertiary alcohol: $(CH_3)_2C(OH)(CH_2CH_3)$.$4$. The $IUPAC$ name of the product $(CH_3)_2C(OH)CH_2CH_3$ is $2-$methylbutan$-2-$ol.Therefore,the correct option is $B$.

Which is the final product obtained by the reaction of Grignard reagent ethyl magnesium bromide with propanone?

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