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(D) Compound $(3)$ is a terminal alkyne $(CH_3-CH_2-C \equiv CH)$.Terminal alkynes possess an acidic hydrogen atom attached to the $sp$-hybridized car

Vedclass · Accepted Answer

Ammoniacal silver nitrate

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(D) Compound $(3)$ is a terminal alkyne $(CH_3-CH_2-C \equiv CH)$.Terminal alkynes possess an acidic hydrogen atom attached to the $sp$-hybridized carbon.Ammoniacal silver nitrate (Tollens' reagent) reacts specifically with terminal alkynes to form a white precipitate of silver acetylide $(CH_3-CH_2-C \equiv C^-Ag^+)$.Compounds $(1)$,$(2)$,and $(4)$ do not contain acidic terminal hydrogen atoms and therefore do not react with Tollens' reagent.Thus,ammoniacal silver nitrate is the most suitable reagent to distinguish compound $(3)$ from the others.

Which is the most suitable reagent among the following to distinguish compound $(3)$ from the others?
$(1) \ CH_3-C \equiv C-CH_3$
$(2) \ CH_3-CH_2-CH_2-CH_3$
$(3) \ CH_3-CH_2-C \equiv CH$
$(4) \ CH_3-CH=CH_2$

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Which is the most suitable reagent among the following to distinguish compound $(3)$ from the others?$(1) \ CH_3-C \equiv C-CH_3$$(2) \ CH_3-CH_2-CH_2-CH_3$$(3) \ CH_3-CH_2-C \equiv CH$$(4) \ CH_3-CH=CH_2$