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(C) The given reaction involves the oxidation of a methyl ketone group $(-COCH_3)$ to a carboxylic acid group $(-COOH)$ while keeping the carbon-carbo

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$I_2$ and $NaOH$ solution with subsequent acidification

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(C) The given reaction involves the oxidation of a methyl ketone group $(-COCH_3)$ to a carboxylic acid group $(-COOH)$ while keeping the carbon-carbon double bond intact.This transformation is characteristic of the haloform reaction.When a methyl ketone is treated with $I_2$ and $NaOH$,it undergoes the iodoform reaction to form a carboxylate salt,which upon subsequent acidification yields the corresponding carboxylic acid.The reaction is:$CH_3-CH=CH-CH_2-COCH_3 \xrightarrow[(ii) 	ext{ Acidification}]{(i) I_2/NaOH} CH_3-CH=CH-CH_2-COOH + CHI_3$

Column $I$ $(Example)$	Column $II$ $(Reaction)$
$a$. $CH_3COCl + H_2 \xrightarrow{Pd-C/BaSO_4} CH_3CHO$	Stephen's reaction
$b$. $C_6H_5CHO \xrightarrow{NaOH, \Delta} C_6H_5CH_2OH + C_6H_5COO^-Na^+$	Cannizzaro's reaction
$c$. $C_6H_6 + CH_3COCl \xrightarrow{AlCl_3} C_6H_5COCH_3$	Friedel-Crafts acylation
$d$. $R-CH_2-COOH \xrightarrow[H_2O]{Br_2/Red P} R-CH(Br)-COOH$	$HVZ$ reaction
$e$. $CH_3-CN \xrightarrow[\text{(ii) } H_2O/H^+]{\text{(i) } SnCl_2/HCl} CH_3CHO$	Stephen's reaction
$f$. $2 CH_3CHO \xrightarrow[\Delta]{NaOH} CH_3-CH=CHCHO$	Aldol condensation

Which is the most suitable reagent for the following conversion?
$CH_3-CH=CH-CH_2-CO-CH_3 \rightarrow CH_3-CH=CH-CH_2-COOH$

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Which is the most suitable reagent for the following conversion?$CH_3-CH=CH-CH_2-CO-CH_3 \rightarrow CH_3-CH=CH-CH_2-COOH$