Which lanthanoid from the following exhibits | vedclass

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(B) The general electronic configuration of lanthanoids is $[Xe] 4f^{1-14} 5d^{0-1} 6s^2$.In the $+3$ oxidation state, the lanthanoids lose two $6s$ e

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$Lu$

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(B) The general electronic configuration of lanthanoids is $[Xe] 4f^{1-14} 5d^{0-1} 6s^2$.In the $+3$ oxidation state, the lanthanoids lose two $6s$ electrons and one $4f$ or $5d$ electron.For $Lu$ (Lutetium, atomic number $71$), the ground state configuration is $[Xe] 4f^{14} 5d^1 6s^2$.In the $+3$ oxidation state, $Lu$ loses two $6s$ electrons and one $5d$ electron, resulting in the configuration $[Xe] 4f^{14}$.Thus, $Lu^{3+}$ has a stable $f^{14}$ configuration.

Which lanthanoid from the following exhibits $f^{14}$ configuration in the $+3$ oxidation state?

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