Which metal sulphide is soluble in excess NH_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $ZnS$,$MnS$,and $FeS$ do not dissolve in excess $NH_3$ solution due to their low $K_{sp}$ values.However,$Cr_2S_3$ can react with excess $NH_3$ to

Vedclass · Accepted Answer

$Cr_2S_3$

Vedclass · Answer

(D) $ZnS$,$MnS$,and $FeS$ do not dissolve in excess $NH_3$ solution due to their low $K_{sp}$ values.However,$Cr_2S_3$ can react with excess $NH_3$ to form a soluble complex: $Cr_2S_3 + 12NH_3 + 6H_2O \rightleftharpoons 2[Cr(NH_3)_6]^{3+} + 3S^{2-} + 6OH^-$. Note: In many standard contexts,$ZnS$ is also considered to form a soluble complex $[Zn(NH_3)_4]^{2+}$ in excess $NH_3$,but among the given choices,$Cr_2S_3$ is specifically noted for its reactivity in this context.

Which metal sulphide is soluble in excess $NH_3$ solution?

Similar Questions

The degree of dissociation of a $0.1 \, M$ $CH_3COOH$ solution is $1.32 \times 10^{-2}$. What will be its dissociation constant $(K_a)$?

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$2NaOH + Zn(OH)_2 \rightarrow Na_2ZnO_2 + 2H_2O$

When $100 \ mL$ of $1 \ M$ $NaOH$ solution is mixed with $10 \ mL$ of $10 \ M$ $H_2SO_4$,the resulting mixture will be

$A$ $20 \ mL$ sample of a $0.2 \ M$ solution of the weak diprotic acid $H_2A$ is titrated with $0.25 \ M \ NaOH$. Molarity of the solution at the second equivalence point is:

$5\%$ ionization occurs in $0.01 \ M$ $CH_3COOH$ solution. Calculate its dissociation constant.

Vedclass Test Series

Exam Paper Generator

Online Exam Module