Which of the following is D in the given reac | vedclass

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(B) The reaction sequence is as follows:$1$. $(CH_3)_3C-CH_2OH$ is a primary alcohol. Oxidation with $PCC$ gives the corresponding aldehyde,$B$,which

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$(CH_3)_2CH-CH_3$

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(B) The reaction sequence is as follows:$1$. $(CH_3)_3C-CH_2OH$ is a primary alcohol. Oxidation with $PCC$ gives the corresponding aldehyde,$B$,which is $(CH_3)_3C-CHO$ (pivalaldehyde).$2$. $B$ $((CH_3)_3C-CHO)$ has no $\alpha$-hydrogen atoms. Therefore,it undergoes the Cannizzaro reaction with concentrated $NaOH$.$3$. The Cannizzaro reaction produces the corresponding alcohol $(A = (CH_3)_3C-CH_2OH)$ and the sodium salt of the carboxylic acid $(C = (CH_3)_3C-COONa)$.$4$. Decarboxylation of the sodium salt of the carboxylic acid $(C)$ with soda lime $(NaOH/CaO, \Delta)$ removes the $-COONa$ group and replaces it with a hydrogen atom.$5$. $(CH_3)_3C-COONa \xrightarrow{NaOH/CaO, \Delta} (CH_3)_3C-H$,which is isobutane ($(CH_3)_3CH$ or $2$-methylpropane).$6$. Comparing this with the options,the structure corresponding to isobutane is represented by option $B$.

Which of the following is $D$ in the given reaction sequence?
$(CH_3)_3C-CH_2OH$ $\xrightarrow{PCC} B$ $\xrightarrow{Conc. NaOH} A + C$ $\xrightarrow{NaOH/CaO, \Delta} D$

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Which of the following is $D$ in the given reaction sequence?$(CH_3)_3C-CH_2OH$ $\xrightarrow{PCC} B$ $\xrightarrow{Conc. NaOH} A + C$ $\xrightarrow{NaOH/CaO, \Delta} D$