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(C) The iodoform test is given by compounds containing the $CH_3CO-$ group or the $CH_3CH(OH)-$ group.$(A)$ $CH_3CH_2OH$ contains the $CH_3CH(OH)-$ gr

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$Ph-C(OH)(CH_3)_2$

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(C) The iodoform test is given by compounds containing the $CH_3CO-$ group or the $CH_3CH(OH)-$ group.$(A)$ $CH_3CH_2OH$ contains the $CH_3CH(OH)-$ group,so it gives the iodoform test.$(B)$ $Ph-CH=CH-CH(OH)CH_3$ contains the $CH_3CH(OH)-$ group,so it gives the iodoform test.$(C)$ $Ph-C(OH)(CH_3)_2$ is a $3^{\circ}$ alcohol. It does not contain the $CH_3CH(OH)-$ group and cannot be oxidized to a methyl ketone. Therefore,it does not give the iodoform test.$(D)$ $CH_3CHO$ contains the $CH_3CO-$ group,so it gives the iodoform test.Thus,the correct option is $C$.

Which of the following is incapable of showing the iodoform test?

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