Which of the following sets of quantum numbers is not possible?

  • A
    $n=3, \ell=2, m=0, s=-1/2$
  • B
    $n=3, \ell=2, m=-2, s=-1/2$
  • C
    $n=3, \ell=3, m=-3, s=-1/2$
  • D
    $n=3, \ell=0, m=0, s=-1/2$

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Similar Questions

Assertion :- In $H$-atom,the energy of $3d$-level is smaller than $4s$-level.
Reason :- In multi-electron species,an orbital with lower value of $(n+\ell)$ has energy smaller than the orbital with larger value of $(n+\ell)$.

Describe the orbitals with the following quantum numbers using $s, p, d, f$ notation:
$(a) n = 1, l = 0$
$(b) n = 3, l = 1$
$(c) n = 4, l = 2$
$(d) n = 4, l = 3$

Match List-$I$ with List-$II$ :
List-$I$ (Quantum numbers)List-$II$ (Orbital)
$A$. $n = 2, l = 1$$I$. $3d$
$B$. $n = 4, l = 0$$II$. $2p$
$C$. $n = 5, l = 3$$III$. $4s$
$D$. $n = 3, l = 2$$IV$. $5f$

Choose the correct answer from the options given below :

The number of electrons that can be present in sub-shells having $m_s$ value of $\frac{-1}{2}$,for $n$ up to $3$.

Which of the sequences given below shows the correct increasing order of energy?

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