Which of the following,after reacting with KI | vedclass

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(D) $CuSO_4$,$K_2Cr_2O_7$,and $HNO_3$ are oxidizing agents that oxidize $I^-$ to $I_2$. $2Cu^{2+} + 4I^- \rightarrow 2CuI + I_2$ $Cr_2O_7^{2-} + 14H^+

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$HCl$

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(D) $CuSO_4$,$K_2Cr_2O_7$,and $HNO_3$ are oxidizing agents that oxidize $I^-$ to $I_2$. $2Cu^{2+} + 4I^- \rightarrow 2CuI + I_2$ $Cr_2O_7^{2-} + 14H^+ + 6I^- \rightarrow 2Cr^{3+} + 7H_2O + 3I_2$ $2HNO_3 + 2HI \rightarrow 2NO_2 + 2H_2O + I_2$ $HCl$ is a non-oxidizing acid and does not oxidize $I^-$ to $I_2$. Therefore,$HCl$ does not liberate iodine.

Which of the following,after reacting with $KI$,does not liberate iodine?

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