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(B) The freezing point depression is given by $\Delta T_f = i \cdot K_f \cdot m$. The freezing point of the solution is $T_f = T_f^\circ - \Delta T_f$

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$0.01 \ M \ NaCl$

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(B) The freezing point depression is given by $\Delta T_f = i \cdot K_f \cdot m$. The freezing point of the solution is $T_f = T_f^\circ - \Delta T_f$. For the highest freezing point,$\Delta T_f$ must be minimum,which implies that the product $i \cdot M$ must be minimum. $(A)$ For $0.1 \ M$ Sucrose,$i = 1$,$i \cdot M = 1 	imes 0.1 = 0.1$. $(B)$ For $0.01 \ M \ NaCl$,$i = 2$,$i \cdot M = 2 	imes 0.01 = 0.02$. $(C)$ For $0.1 \ M \ NaCl$,$i = 2$,$i \cdot M = 2 	imes 0.1 = 0.2$. $(D)$ For $0.01 \ M \ Na_2SO_4$,$i = 3$,$i \cdot M = 3 	imes 0.01 = 0.03$. Since $0.01 \ M \ NaCl$ has the lowest $i \cdot M$ value,it has the highest freezing point.

Which of the following aqueous solutions has the highest freezing point?

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